If tan a = 2 root 2 then the value of Cos A minus sin a upon Cos A + sin a is
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Let a triangle ABC in which right angled at B and angle A is equal to theta degree….Now tan a is equal to 2 root 2 and so, tan a is equal to BC/AB=2√2==>BC=2√2AB.Now let AB=X.Then BC =2√2X.By usuing Pythagoras theorem we have AC squire = AB square + BC square..==>AC=3X.Now (cosA-sinA)/(cosA+sinA)=-1