Given\xa0tan2A=cot(A−180)⇒cot(90−2A)=cot(A−180)[∵tanθ=cot(90−θ)]Comparing angles we get90−2A=A−18⇒90+18=A+2A⇒3A=108⇒A=108\u200b/3⇒A=36∘
If tan 2A=cot(A-18°),where 2A is an acute angle,find the value of A
Dinesh Prasad Sunder
Asked: 3 years ago2022-11-10T11:44:03+05:30
2022-11-10T11:44:03+05:30In: Class 10
If tan 2A=cot(A-18°), where 2A is an acute angle, find the value of A.
If tan 2A=cot(A-18°), where 2A is an acute angle, find the value of A.
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Usman Lal Nazareth
Asked: 3 years ago2022-11-07T16:22:27+05:30
2022-11-07T16:22:27+05:30In: General Awareness
If tan 2A = cot (A – 18°), where 2A is an acute angle. Find the value of A.
If tan 2A = cot (A – 18°), where 2A is an acute angle. Find the value of A.
Leave an answer
Leave an answer
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Given that tan 2A = cot (A – 18°)
⇒ cot (90° – 2A) = cot (A – 18°) [∵ tan θ = cot (90 – θ)]
⇒ 90° – 2A = A – 18°
⇒ 108° = 3A
⇒ A = 108° / 3 = 36°
Hence the value of A is 36°.
Kiran Sandal
Asked: 3 years ago2022-11-07T14:16:43+05:30
2022-11-07T14:16:43+05:30In: Class 10
If tan 2A=cot (A-18°), where 2A is an acute angle, Find the value of A.
If tan 2A=cot (A-18°), where 2A is an acute angle, Find the value of A.
Leave an answer
Leave an answer
-
Right
36
36
Hassan Nayan De
Asked: 3 years ago2022-11-06T13:33:27+05:30
2022-11-06T13:33:27+05:30In: General Awareness
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
Leave an answer
Leave an answer
-
tan 2A = cot (A – 18°)
cot (90 – 2A) = cot (A – 18)
90 – 2A = A – 18
3A = 108°
∴ A = 36°
36
A=36°