If one of roots of x2 + ax + 4 = 0 is twice the other root, then the value of ‘a’ is
A) 8√2
B) √2
C) -3√2
D) -2√2
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Correct option is (C) -3√2
Let \(\alpha\;and\;2\alpha\) are roots of \(x^2+ax + 4 = 0\) _______________(1)
\(\therefore\) Product of roots = 4
\(\Rightarrow\) \(2\alpha^2=4\)
\(\Rightarrow\) \(\alpha^2=2\)
\(\Rightarrow\) \(\alpha=\pm\sqrt2\) ______________(2)
And sum of roots = -a
\(\therefore\) \(-a=\alpha+2\alpha\)
\(=3\alpha\)
\(=3(\pm\sqrt2)\) (From (2))
\(=\pm3\sqrt2\)
\(\therefore a=\mp3\sqrt2\)
Possible values of a are \(3\sqrt{2}\;or\;-3\sqrt{2}.\)
Correct option is C) -3√2