If one of its zero of polynomial f (x)=4×2 -8k (x) -9 is negative of other find the value of k
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Let, the two zeroes of the polynomial f(x) = 4×2 – 8kx – 9 be α and -α.Comparing f(x) = 4×2\xa0- 8kx – 9 with ax2+bx+c we geta = 4; b = -8k and c = -9.Sum of the zeroes = α + (-α) ={tex}-\\frac ba=\\;-\\frac{-8k}4 {/tex}0 = 2kk = 0