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Binita Banerjee
Asked: 2022-11-08T15:37:28+05:30 In:

If M is molecular of solvent, `K_(b)` is molal elevation constant, `T_(b)` is its boiling point, `P^(@)` is its vapour pressure at temperature T and `P_(s)` is vapour pressure of its solution having a non-volatile solute at T K, then
A. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xxM`
B. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b)xxM)`
C. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b))xx(M)/(1000)`
D. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xx(M)/(1000)`

If M is molecular of solvent, `K_(b)` is molal elevation constant, `T_(b)` is its boiling point, `P^(@)` is its vapour pressure at temperature T and `P_(s)` is vapour pressure of its solution having a non-volatile solute at T K, then
A. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xxM`
B. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b)xxM)`
C. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b))xx(M)/(1000)`
D. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xx(M)/(1000)`
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1 Answer

  1. Correct Answer – D
    `(p^(@)-p_(s))/(p^(@))=(n)/(N)=(“Molality”xxM)/(1000)`
    `”and ” “molality”=(DeltaT_(b))/(K_(b))” ” (becauseDeltaT_(b)=K_(b)xxm)`

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