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Lakshmi Prasad Shetty
Asked: 2022-11-11T20:26:41+05:30 In:

If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?
A. `m_(1)/m_(2)=E_(2)/E_(1)`
B. `E_(1)E_(2)=m_(1)m_(2)`
C. `m_(1)E_(2)=E_(1)m_(2)`
D. `(m_(1)+m_(2))=(E_(1)+E_(2))`

If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?
A. `m_(1)/m_(2)=E_(2)/E_(1)`
B. `E_(1)E_(2)=m_(1)m_(2)`
C. `m_(1)E_(2)=E_(1)m_(2)`
D. `(m_(1)+m_(2))=(E_(1)+E_(2))`
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  1. Correct Answer – C
    The correct formulae that expresses the law of
    equivalent correctly is
    `m_(1)E_(2)=E_(1)m_(2)`

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Mukti Goel
Asked: 2022-11-02T01:05:02+05:30 In:

If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?
A. `m_E_=m_(2)E_(2)`
B. `m_(1)m_(1)=E_(1)E_`
C. `m_(1)E_(2)=m_(2)E_(1)`
D. `sqrt(m_(1)//E_(1))=sqrt(m_(2)//E_(2))`

If `m_(1)` and `m_(2)` are masses of two reactants in any reaction, having their gram equivalent masses `E_(1)` and `E_(2)` respectively, which of the following equatios represents the law of equivence correctly?
A. `m_E_=m_(2)E_(2)`
B. `m_(1)m_(1)=E_(1)E_`
C. `m_(1)E_(2)=m_(2)E_(1)`
D. `sqrt(m_(1)//E_(1))=sqrt(m_(2)//E_(2))`
Parabola
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  1. Correct Answer – 3
    According to the law of equivalence, the number of equivalent of different substances (reactants and products) involved in a given chemical reaction are always equal. Thus
    `m_(1)/E_(1)=m_(2)/E_(2)`
    or `m_(1)E_(2)=m_(2)E_(1)`

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