If an air bubbles rises from the bottom of a mercury tank to the top its volume becomes `1(1)/(2)` times. When normal pressure is `76 cm` of `Hg` then the depth of the `Hg` tank is
A. `38 cm`
B. `123 cm`
C. `76 cm`
D. `49 cm`
A. `38 cm`
B. `123 cm`
C. `76 cm`
D. `49 cm`
Correct Answer – A
`P_(1)V_(1) = P_(2)V_(2) , (H + h)V_(1) = HV_(2)`