If A and B are the 2 independent events, have P(A) = 0.6 and P(B) = 0.2,then what will be P((A∪B)’)?
1. 0.56
2. 0.32
3. 0.68
4. 0.44
1. 0.56
2. 0.32
3. 0.68
4. 0.44
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Correct Answer – Option 2 : 0.32
Concept:
For any two independent events A and B, if P(A) and P(B) are their probability of occurring then:
Calculation:
Given P(A) = 0.6 and P(B) = 0.2
P(A ∩ B) = P(A) × P(B)
⇒ P(A ∩ B) = 0.6 × 0.2 = 0.12
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
⇒ P(A ∪ B) = 0.6 + 0.2 – 0.12
⇒ P(A ∪ B) = 0.68
P((A ∪ B)’) = 1 – P(A ∪ B)
⇒ P((A ∪ B)’) = 1 – 0.68
⇒ P((A ∪ B)’) = 0.32