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Samir Bhatti
Asked: 2022-11-11T05:47:23+05:30 In:

How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?
A. 0.125 mol , 7.32 g
B. 7.32 mol , 0.125 g
C. 0.125 mol, 0.125 g
D. 7.32 mol , 7.32 g

How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?
A. 0.125 mol , 7.32 g
B. 7.32 mol , 0.125 g
C. 0.125 mol, 0.125 g
D. 7.32 mol , 7.32 g
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  1. Correct Answer – A
    Number of moles `= (MV)/(1000)=(0.5xx250)/(1000)=0.125`
    Mass of NaCl `=58.5xx0.125=7.32g`]

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Megha Bassi
Asked: 2022-11-06T18:38:15+05:30 In:

How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?

How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?
Parabola
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Leave an answer

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1 Answer

  1. Number of moles of `NaCl = (MV)/(1000)`
    `= (0.5 xx 50)/(1000)=0.025`
    `NaCl rarr Na^(+) +Cl^(-)`
    Number of moles of `Na^(+)=` Number of moles of NaCl
    `= 0.025`
    Number of ions of `Na^(+)=0.025 xx 6.023 xx 10^(23)`
    `= 1.505 xx 10^(22)`.

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