From a rectangle ABCD of area 812 cm2, a semicircular part with diameter CD and area 98π cm2 are removed, find the perimeter of the remaining figure.
1. 125 cm
2. 135 cm
3. 130 cm
4. 164 cm
1. 125 cm
2. 135 cm
3. 130 cm
4. 164 cm
Correct Answer – Option 3 : 130 cm
Given –
area of rectangle = 812 cm2, area of semicircle = 98π cm2
Formula used –
area of rectangle = length × breadth
area of semicircle = (1/2) × π × radius2
Solution –
Let the radius of the semi – circle is r cm.
⇒ (1/2) × π r2 = 98π
⇒ r2 = 196
⇒ r = 14 cm
⇒ diameter of the semi – circle = 28 cm
⇒ diameter of semi – circle = side of rectangle CD = 28 cm
⇒ area of rectangle = 812 cm2
⇒ BC × CD = 812
⇒ BC × 28 = 812
⇒ BC = 29 cm
⇒ We have to find perimeter of remaining figure so,
⇒ perimeter = AB + BC + AD + (1/2) × perimeter of the circle
⇒ perimeter = 28 + 29 + 29 + (1/2) × (2πr)
⇒ perimeter = 58 + 28 + (22/7) × 14
⇒ perimeter = 130 cm
∴ perimeter of remaining figure = 130 cm.