Find the sum of first 10 multiples of 3
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Sorry the formula is Sn=n÷2(2a+(n-1)×d)
165….
The no.of terms is 10 so, n=10The first term is 3 so, a=3The the multiples of 3 means the common difference is also 3 so,d=3Then substitute the value of (a,n,d)in the formula. Sn=n÷2(2n+(n-1)+d)
165