Find the roots of the following quadratic equation, if they exist, by the method of completing the square:
x2 + 5 = -6x
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The given Q.E. is x2 + 5 = -6x
⇒ x2 + 6x = -5
⇒ (x)2 + 2.(x).3 = -5
Now L.H.S. is of the form a2 + 2ab where b = 3.
Adding b2 = 32 on both sides we get
x2 + 2(x)(3) + 32 = -5 + 32
(x + 3)2 = -5 + 9 = 4
∴ x + 3 = 74 = ± 2
⇒ x = +2 – 3 or – 2 – 3
\(\therefore\) x= -1 or -5 are the roots of the given Q.E.