Find the number which is nearest to 3105 and is exactly divisible by 21.
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Find the number which is nearest to 3105 and is exactly divisible by 21.
Find the number which is nearest to 3105 and is exactly divisible by 21.
On dividing 3105 by 21, we get 18 as remainder.
Number to be added to 3105 = (21 – 18) – 3.
Hence, required number = 3105 + 3 = 3108.