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Mukti Kabeer Kumar
Mukti Kabeer Kumar
Asked: 3 years ago2022-11-11T18:22:22+05:30 2022-11-11T18:22:22+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

xi510152025
fi74635

Find the mean deviation from the mean for the following data :

xi510152025
fi74635
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  1. 64474
    2022-10-31T07:57:34+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation from the mean. 

    Formula Used: Mean Deviation =   \(\frac{\Sigma f|d_i|}{N}\)  

    Explanation. 

    Here we have to calculate the mean deviation from Mean 

    So, Mean = \(\frac{\Sigma f_ix_i}{f_i}\)  

    xi fi Cumulative Frequency |di|=|xi – Mean| Fi|di|
    5 7 35 9 63
    10 4 40 4 16
    15 6 90 1 6
    20 3 60 6 18
    25 5 125 11 55
    Total = 25 Total = 350 Total = 158

    Mean = \(\frac{350}{25}\) =14 

    Mean Deviation = \(\frac{\Sigma f|d_i|}{N}\)  

    Mean deviation for given data = \(\frac{158}{25}\) = 6.32

    Hence, The mean Deviation is 6.32.

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Narayan Chandra Sachdeva
Narayan Chandra Sachdeva
Asked: 3 years ago2022-11-08T23:48:05+05:30 2022-11-08T23:48:05+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

Classes0-100100-200200-300300-400400-500500-600600-700700-800
Frequencies489107543

Find the mean deviation from the mean for the following data :

Classes0-100100-200200-300300-400400-500500-600600-700700-800
Frequencies489107543
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  1. 8e491
    2022-11-10T01:20:34+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation 

    Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. 

    Here we have to calculate the mean deviation from the mean. So, 

    Mean = \(\Sigma \frac{f_ix_i}{n}\) 

    Here, Mean =  \(\frac{17900}{50}\) 

    Therefore, Mean = 358

    Class Interval Xi Fi FiXi di=(xi-Mean) Fidi
    0-100 50 4 200 308 1232
    100-200 150 8 1200 208 1664
    200-300 250 9 2250 108 972
    300-400 350 10 3500 8 80
    400-500 450 7 3150 92 644
    500-600 550 5 2750 192 960
    600-700 650 4 2600 292 1168
    700-800 750 3 2250 392 1176
    Total = 50 Total = 17900 Total = 7896

    Mean Deviation = \(\frac{\Sigma f|di|}{N}\)  

    Mean deviation for given data \(\frac{7896}{50}\) = 157.92 

    Hence, The Mean Deviation is 157.92

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Sai Raj Pall
Sai Raj Pall
Asked: 3 years ago2022-11-04T23:40:47+05:30 2022-11-04T23:40:47+05:30In: General Awareness

Find the mean deviation from the mean for the following data

xi579101215
fi862226

Find the mean deviation from the mean for the following data

xi579101215
fi862226
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  1. 65411
    2022-11-01T01:55:18+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation from the mean. 

    Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. 

    Here we have to calculate the mean deviation from Mean 

    So, Mean = \(\frac{\Sigma f_ix_i}{f_i}\) 

    xi fi Cumulative Frequency(xifi) |di| = |xi-Mean| Fi|di|
    5 8 40 4 32
    7 6 42 2 12
    9 2 18 0 0
    10 2 20 1 2
    12 2 24 3 6
    15 6 90 6 36
    Total = 26 Total = 234 Total = 88

    Mean = \(\frac{234}{26}\) = 9 

    Mean Deviation = \(\frac{\Sigma f|di|}{N}\) 

    Mean deviation for given data = \( \frac{88}{26}\) = 3.3

    Hence, The mean Deviation is 3.3.

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Urmila Baber Kaul
Urmila Baber Kaul
Asked: 3 years ago2022-11-04T08:53:27+05:30 2022-11-04T08:53:27+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

Size:13579111315
Frequency:334147434

Find the mean deviation from the mean for the following data :

Size:13579111315
Frequency:334147434
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  1. fe1c5
    2022-11-04T14:45:02+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given.

    To Find: Calculate the Mean Deviation from the mean. 

    Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. 

    Here we have to calculate the mean deviation from Mean 

    So, Mean = \(\frac{\Sigma f_ix_i}{f_i}\) 

    Mean of the given data is  \(\frac{433}{20}\)  = 21.65

    xi fi Cumulative Frequency(xifi) |di| = |xi-Mean| Fi|di|
    20 6 120 1.65 9.9
    21 4 84 0.65 2.6
    22 5 110 0.35 1.75
    23 1 23 1.35 1.35
    24 4 96 2.35 9.40
    Total = 20 Total = 433 Total = 25

    Mean Deviation = \(\frac{\Sigma f|d_i|}{N}\) 

    Mean deviation for given data is \(\frac{25}{20}\) =1.25

    Hence, The mean Deviation is 1.25.

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Uday Raj Pingle
Uday Raj Pingle
Asked: 3 years ago2022-11-03T20:37:21+05:30 2022-11-03T20:37:21+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

xi1030507090
fi42428168

Find the mean deviation from the mean for the following data :

xi1030507090
fi42428168
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  1. ba596
    2022-10-31T00:05:01+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation from the mean. 

    Formula Used: Mean Deviation =  \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. Here we have to calculate the mean deviation from Mean 

    So, Mean = \(\frac{\Sigma f_ix_i}{f_i}\) 

    xi fi Cumulative Frequency (xifi) |di| = |xi-Mean| Fi|di|
    5 7 35 9 63
    10 4 40 4 16
    15 6 90 1 6
    20 3 60 6 18
    25 5 125 11 55
    Total = 25 Total = 350 Total = 158

    Mean = \(\frac{350}{25}\) =14 

    Mean Deviation =  \(\frac{\Sigma f|d_i|}{N}\) 

    Mean deviation for given data = \(\frac{158}{25}\) = 6.32

    Hence, The mean Deviation is 6.32.

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Deep Bhai Viswanathan
Deep Bhai Viswanathan
Asked: 3 years ago2022-10-30T23:47:32+05:30 2022-10-30T23:47:32+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

Size:2021222324
Frequency:64514

Find the mean deviation from the mean for the following data :

Size:2021222324
Frequency:64514
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  1. 45043
    2022-10-31T14:35:24+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation from the mean. 

    Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. 

    Here we have to calculate the mean deviation from Mean 

    So, Mean = \(\frac{\Sigma f_ix_i}{f_i}\)  

    Mean of given Data = \(\frac{4000}{80}\) =50

    xi fi Cumulative Frequency(xifi) |di| = |xi=Mean| Fi|di|
    10 4 40 40 160
    30 24 720 20 480
    50 28 1400 0 0
    70 16 1120 20 320
    90 8 720 40 320
    Total = 80 Total = 4000 Total = 1280

    Mean =  \(\frac{4000}{80}\)  = 50

    Mean Deviation =   \(\frac{\Sigma f|d_i|}{n}\) 

    Mean deviation for given data = \(\frac{1280}{80}\) = 16

    Hence, The mean Deviation is 16

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Padama Anil Chokshi
Padama Anil Chokshi
Asked: 3 years ago2022-10-29T16:48:51+05:30 2022-10-29T16:48:51+05:30In: General Awareness

Find the mean deviation from the mean for the following data :

Classes95-105105-115115-125125-135135-145145-155
Frequencies91316263012

Find the mean deviation from the mean for the following data :

Classes95-105105-115115-125125-135135-145145-155
Frequencies91316263012
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  1. 02c04
    2022-11-03T06:23:30+05:30Added an answer about 3 years ago

    Given, Numbers of observations are given. 

    To Find: Calculate the Mean Deviation 

    Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

    Explanation. 

    Here we have to calculate the mean deviation from the mean. So, 

    Mean = \(\Sigma \frac{f_ix_i}{n}\)  

    Here, Mean = \(\frac{13630}{106}\) = 128.6

    Therefore, Mean = 49

    Class  Interval Xi Fi FiXi di=(x-mean) Fi|di|
    95-105 100 9 900 -28.6 257.4
    105-115 110 13 1430 -18.6 241.8
    115-125 120 16 1920 -8.6 137.6
    125-135 130 26 3380 1.4 36.4
    135-145 140 30 4200 12.4 372
    145-155 150 12 1800 22.4 268.8
    N=106  Total = 13630 Total = 1314

    Mean Deviation = \(\frac{\Sigma f|d_i|}{N}\) 

    Mean deviation for given data = \(\frac{1314}{106}\) = 12.39

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