Find the equation of the line having inclination 135° and making x-intercept 7.
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Find the equation of the line having inclination 135° and making x-intercept 7.
Find the equation of the line having inclination 135° and making x-intercept 7.
Given, Inclination of line = 0 = 135°
∴ Slope of the line (m) = tan 0 = tan 135°
= tan (90° + 45°)
= – cot 45° = – 1 x-intercept of the required line is 7.
∴ The line passes through (7, 0). Equation of the line in slope point form is y1 – y = m(x – x1)
∴ The equation of the required line is y — 0 = – 1 (x – 7)
∴ y = -x + 7
∴ x + y – 7 = 0
y= aX+b:–>, where a is the slope of the line and b, is the y-intercept.
when x takes a value of 0 then aX = 0 and then y =b (that’s why b is the y-intercept ).
Accordingly, calculate the slope which is tan(theta) ( sin(theta)/cos(theta)= y/x)
put that value to be the (a) in the equation, and put the y-intercept (+7) in place of b
final eq–> y= tan(135)X+7