Find the equation of a line which makes an angle of tan– 1 (3) with the x–axis and cuts off an intercept of 4 units on the negative direction of y–axis.
Given: The equation which makes an angle of tan–1(3) with the x–axis and cuts off an intercept of 4 units on the negative direction of y–axis.
To Find: The equation of the line?
The formula used: The equation of the line is y = mx + c
Explanation: Here, angle θ = tan–1(3)
So, tan θ = 3
The slope of the line is, m = 3
And, Intercept in the negative direction of y–axis is (0, -4)
Now, The required equation of the line is y = mx + c
y = 3x – 4
Hence, The equation of the line is y = 3x – 4.
Given:
The equation which makes an angle of tan– 1(3) with the x–axis and cuts off an intercept of 4 units on the negative direction of y–axis
By using the formula,
The equation of the line is y = mx + c
Here, angle θ = tan– 1(3)
So, tan θ = 3
The slope of the line is, m = 3
And, Intercept in the negative direction of y–axis is (0, -4)
The required equation of the line is y = mx + c
Now, substitute the values, we get
y = 3x – 4
∴ The equation of the line is y = 3x – 4.