77/8
22=2πr22=2*22\\7*rr=7/2
77/8 cm square.
Circumference=2πr2*22/7*r=22Therefore r=7/2Area of quadrant=1/4*π*r*rTherefore answer 77/8

Circumferences of a circle\xa0{tex}= 2 \\pi r{/tex}{tex}\\Rightarrow 2 \\pi r = 44{/tex}{tex}\\Rightarrow 2 \\times \\frac { 22 } { 7 } \\times r = 44{/tex}{tex}\\Rightarrow{/tex}\xa0r = 7 cm{tex}\\therefore{/tex}\xa0Area of the quadrant{tex}= \\left( \\frac { 1 } { 4 } \\times \\frac { 22 } { 7 } \\times 7 \\times 7 \\right) \\mathrm { cm } ^ { 2 }{/tex}{tex}= \\frac { 77 } { 2 } \\mathrm { cm } ^ { 2 }{/tex}{tex}= 38.5 cm^2{/tex}

circumference of the circle= 44cm2πr=442×22/7×r=4444/7×r=44r=44×7/44r=7cmar. of quadrant= 1/4πr² =1/4×22/7×7² =77/2 =38.5(hope this is correct)
First use circumference then area of quadrant which is 1/4 pie (r)2 then solve easily

9.625cm2
77/8
9.625cm2