Find the 4th term from the end of the AP 11,-8,-5,……….49
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Given A.P:-11,-8,-5,.….,49first term (a) = -11,{tex}Common\\: difference (d)\\\\=a_{2}-a_{1}\\\\=-8-(-11)\\\\=-8+11\\\\=3{/tex}Now,Rearranging the terms , from last to first ,we get49,46,…,-5,-8,-11first term (a) = 49,d = 46-49 = -3{tex}Fourth\\:term (a_{4})=a+3d{/tex}{tex}=49+3\\times (-3)\\\\=49-9\\\\=40{/tex}Therefore,{tex}Fourth\\:term\\:the \\:last \\:of\\\\the \\:A.P = 40{/tex}\xa0
4th term of ap is 29