-32
The 11th term is -32
The 11th term is -32

For this let reverse the AP..now first term = a = -62common difference = d = 3now 11th term from this side is…A11 = a+10d = -62+10(3) =-62 + 30 = -32hence 11th term from the last is -32

an=a + (n-1)d-62=10+(n-1)(-3)-62=10-3n+33n=75n=25term 15 from the first term = term 11 from last term\xa01,2,3,4,5,6,7,8,9,10,11,12,13,14, 15, 16,17,18,19,20,21,22,23,24,25a15=a+14x-3a15=10-42 = – 32
Use this formula for your ans ;l-(n-1)d in which l is the last term i.e -62

First we have to find the number of terms Firt term(a)=10Common difference(d)=(-3)An=a+(n-1)d-62=10 +(n-1)(-3)-62-10=3-3n-72-3=-3n75=3nn=25Now As we have to find the 11th term from the last therefore First term(a)=(-62)Common difference(d)=(3) Then A11=a+(n-1)d A11 = -62+ (25-1)(3) (n=25) A11= -62 + (24)(3) A11 = -62+72 A11=10
Dhh