For this let reverse the AP..now first term = a = 62common difference = d = 3now 11th term from this side is…A11 = a+10d = 62+10(3) =62 + 30 = 32hence 11th term from the last is 32
Find the 11th term from the last term (towards the first term) of the AP:10,7,4,…………,62
Satish Pratap Mohanty
Asked: 2 years ago20221107T02:27:34+05:30
20221107T02:27:34+05:30In: Class 10
Find the 11th term from the last term (towards the first term) of the AP:10,7,4,….,62.
Find the 11th term from the last term (towards the first term) of the AP:10,7,4,….,62.
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Leave an answer
Poonam Devi
Asked: 2 years ago20221104T07:44:20+05:30
20221104T07:44:20+05:30In: Class 10
Find the 11th term from the last term (towards the first term) of the ap : 10,7,4…..62.
Find the 11th term from the last term (towards the first term) of the ap : 10,7,4…..62.
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Abhishek Goel
Asked: 2 years ago20221101T18:57:48+05:30
20221101T18:57:48+05:30In: Class 10
Find the 11th term from the last term (towards the first term ) of the AP:10,7,4…,62
Find the 11th term from the last term (towards the first term ) of the AP:10,7,4…,62
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an=a + (n1)d62=10+(n1)(3)62=103n+33n=75n=25term 15 from the first term = term 11 from last term\xa01,2,3,4,5,6,7,8,9,10,11,12,13,14, 15, 16,17,18,19,20,21,22,23,24,25a15=a+14x3a15=1042 = – 32
Use this formula for your ans ;l(n1)d in which l is the last term i.e 62
Nidhi Raju
Asked: 2 years ago20221029T04:11:33+05:30
20221029T04:11:33+05:30In: Class 10
Find the 11th term from the last term (towards the first term)of AP :10,7,4…,62…
Find the 11th term from the last term (towards the first term)of AP :10,7,4…,62…
Leave an answer
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First we have to find the number of terms Firt term(a)=10Common difference(d)=(3)An=a+(n1)d62=10 +(n1)(3)6210=33n723=3n75=3nn=25Now As we have to find the 11th term from the last therefore First term(a)=(62)Common difference(d)=(3) Then A11=a+(n1)d A11 = 62+ (251)(3) (n=25) A11= 62 + (24)(3) A11 = 62+72 A11=10
Dhh
32
The 11th term is 32
The 11th term is 32