Find smallest number which leaves reminders 8and 12 when divided by 28 and 32 respectively
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The LCM of 28 and 3228 = 2× 2 × 7=22×732 = 2 × 2 × 2 × 2 × 2=25LCM = 25 × 7 = 224Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32= LCM of 8 & 12 = 224 – 20 = 204Therefore, 204 is smallest number which when divided by 28 and 32 leaves remainder 8 and 12 respectively.