Fifty millilitres of pure and dry `O_2` was subjected to silent electric discharge and on cooling to the original temperature, the volume of the ozonised oxygen was found to be 47 ml. The gas was then absorbed in turpentine oil the volume of the remainig gas was found to e 41 ml. Find the molecular formula of ozon.
Volume of `O_2=50ml`
Let the formula of ozone be `O_x`
Volume of `O_2` (not converted to `O_x)+`ozone produced `=47ml`
Volume of `O_2` left (not converted to `O_x)=41ml`
Since ozone is absorbed in turpentine oil,
Volume of `O_2` converted to `O_x=50-41`
`=9ml`
Volume of ozone produced `=47-41`
`=6ml`
`{:(O_2,rarr,O_x),(9ml,,6ml),(9 mol es,,6 mol es):}`
Appying `POAC` rule (principle of atom conservation) for the O atom, we get
Number of O atoms `xx` moles of `O_2=` Number of O atoms `xx` moles of `O_x`
`=2xx9=x xx6`
`impliesx=3`
Hence, the formula of ozone is `O_3`.