Equation of hyperbola whose asymptotes are 3x ± 5y = 0 and vertices are (± 5, 0) is
1. 9x2 – 25y2 = 225
2. 25x2 – 9y2 = 225
3. 5x2 – 3y2 = 225
4. 3x2 – 5y2 = 225
1. 9x2 – 25y2 = 225
2. 25x2 – 9y2 = 225
3. 5x2 – 3y2 = 225
4. 3x2 – 5y2 = 225
Correct Answer – Option 1 : 9x2 – 25y2 = 225
Concept:
The equation of the hyperbola is:
\(\frac{{{x^2}}}{{{a^2}}} – \frac{{{y^2}}}{{{b^2}}} = 1\)
The vertices are (± a, 0)
The asymptotes are the straight lines:
y = (b/a)x and y = -(b/a)x.
Given:
Vertices are (± 5, 0)
Asymptotes are: 3x ± 5y = 0
Analysis:
5y = 3x & 5y = -3x
\(y = \left( {\frac{3}{5}} \right)x\;\& \;y = – \left( {\frac{3}{5}} \right)x\)
∴ a = 5 and b = 3
Equation of hyperbola:
\(\frac{{{x^2}}}{{25}} – \frac{{{y^2}}}{9} = 1\)
9x2 – 25y2 = 225