Equation of a line having slope 3 and the point (3, 2) lies on the line
1. 3y – x – 3 = 0
2. y – 3x + 7 = 0
3. y + 3x – 11 = 0
4. 3y + x – 9 = 0
1. 3y – x – 3 = 0
2. y – 3x + 7 = 0
3. y + 3x – 11 = 0
4. 3y + x – 9 = 0
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Correct Answer – Option 2 : y – 3x + 7 = 0
Concept:
The general equation of a line is y = mx + c
where m is the slope and c is any constant
Equation of a line with slope m and passing through (x1, y1)
(y – y1) = m (x – x1)
Equation of a line passing through (x1, y1) and (x2, y2) is:
\(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\)
Calculation:
Given the line has the slope 3 and passes through (3, 2)
∴ Equation of the line is
(y – y1) = m (x – x1)
⇒ y – 2 = 3 (x – 3)
⇒ y – 3x + 7 = 0