Determine the size of a spherical balloon filled with hydrogen at 30°C and atmospheric pressure for lifting 400Kg payload. Atmospheric air is at temperature of 27°C and barometer reading is 75cm of mercury.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Determine the size of a spherical balloon filled with hydrogen at 30°C and atmospheric pressure for lifting 400Kg payload. Atmospheric air is at temperature of 27°C and barometer reading is 75cm of mercury.
Determine the size of a spherical balloon filled with hydrogen at 30°C and atmospheric pressure for lifting 400Kg payload. Atmospheric air is at temperature of 27°C and barometer reading is 75cm of mercury.
Given that:
Hydrogen temperature = 300C = 303K
Load lifting = 400Kg
Atmospheric pressure = 13.6 × 103 × 0.75 × 9.81 = 1.00 × 105 N/m2 = 1.00 bar
Atmospheric Temperature = 270C = 300K
The mass that can be lifted due to buoyancy force,
So the mass of air displaced by balloon(ma ) = Mass of balloon hydrogen gas (mb) + load lifted …(i)
Since PV = mRT; ma = Pa Va /RTa ; R = 8314/29 = 287 KJ/Kgk For Air; 29 = Mol. wt of air
= 1.00 × 105 × V/ 287 × 300 = 1.162V Kg …(ii)
Mass of balloon with hydrogen
mb = PV/RT = 1.00 × 105 × V/ (8314/2 × 300) = 0.08V Kg …(iii)
Putting the values of (ii) and (iii) in equation (i)
1.162V = 0.08V + 400
V = 369.67 m3
But we know that the volume of a balloon (sphere) = 4/3Πr3
322 = 4/3Πr3
r = 4.45 m