Can anyone prove that sum of any 3 consecutive natural no is divisible by6
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No I was just kidding
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In short
Let no be x , x+1 , x+2 !! Now sum of these three = x+x+1+x+2 = 3x+3 = 3(x+1) !! By euclid. Lemma …it is in form.of bq +r where r is 0 . it is divisible by 3
Yes so easy
It\’s not a proof you have to prove it theoretically
It is 6 divisible by 3
1+2+3
Sorry no 6 its3