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Baalkrishan Pratap Wadhwa
Asked: 2022-11-11T13:52:56+05:30 In:

Calculate the volume of hydrogen liberated at `27^(@)C and 760mm` pressure by treating 1.2g of magnesium with excess of hydrochloric acid.

Calculate the volume of hydrogen liberated at `27^(@)C and 760mm` pressure by treating 1.2g of magnesium with excess of hydrochloric acid.
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  1. The balanced equation is
    `underset(24g)underset(1″mol”)(Mg)+2HCl to MgCl_(2)+underset(22.4″litre of NTP”)underset(1″mol”)(H_(2))`
    24g of Mg liberates hydrogen=22.4litre
    1.2g Mg will libertes hydrogen=`(22.4)/(24)xx1.2=1.2″litre`
    Volume of hydrogen under give condition can be calculated by applying `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
    `{:(,P_(1)=760mm,P_(2)=760mm),(,T_(1)=273K,T_(2)=(27+273)=300K),(,V_(1)=1.12″litre”,V_(2)=?):}`
    `V_(2)=(760xx1.12)/(273)xx(300)/(760)=1.2308″litre”`

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