Calculate the pressure exerted by 110 g of carbon dioxide in a vessel of 2 L capacity at `37^(@)C`. Given that the van der Waals constants are a=3.59 `L^(2) atm mol^(-2)` and b=0.0427 L `mol^(-1)`. Compare the value with the calculated value if the gas were considered as ideal.
According to van der Waals equation,
`(p+(an^(2))/(V^(2)))(v-nb)=nRT “or “P=(nRT)/(V-nb)-(an^(2))/(V^(2))`
Here, `n=(110)/(44)=2.5` moles. Substituting the given values, we get
`P=((2.5 mol)(0.0821″ L atm “K^(-1) mol^(-1)))/((2 L-2.5 molxx0.0427 L mol^(-1)))-((3.59 L^(2) atm” mol”^(-2))(2.5 mol^(-2)))/((2 L)^(2))`
`33.61 atm-5.61 atm=28.0`
If the gas were considered is ideal gas, applying ideal gas equation, PV=nRT, we get
`P=(nRT)/(V)=((2.5 mol)(0.0821″ L atm mol”^(-1))(310 K))/(2 L)=31.8 atm`