Calculate mole fraction of ethyl alcohol and water in a solution containing 46 g ethyl and 36g water.
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`n_(C_(2)H_(5)OH)=(46)/(46)=1`
`n_(H_(2)O)=(36)/(18)=2`
`X_(C_(2)H_(5)OH)=(n_(C_(2)H_(5)OH))/(n_(C_(2)H_(5)OH))=(1)/(1+2)=(1)/(3)`
`X_(H_(2)O)=1-(1)/(3)=(2)/(3)`