Bleaching powder contains a salt of an oxoacid as one of its components. The anhydride of that oxoacid is:
A. `CI_(2)O`
B. `CI_(2)O_(7)`
C. `CIO_(2)`
D. `CI_(2)O_(6)`
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Correct Answer – A
Bleaching powder` to CaOCl_(2)`
`to Ca^(2+)(Ocl^(-))(Cl^(-))`
It is salt of hypochlorous acid HOCl, Anhydride of HOCl is `Cl_(2)O`
`2HOCl to Cl_(2)O+H_(2)O`
Correct Answer – A
`CaOCl_(2)=Ca(OCl)Cl`
`OCl^(-) rarr` Hypochlorite ion
which is anion of `HOCl`
Anhydride of `HOCl=Cl_(2)O`
Correct Answer – C
Milli mole of Hypo `=0.25xx48`
`=2xx` milli moles of `Cl_(2)`
milli mole of `Cl_(2)=(0.25xx48)/2=6` milli mole of `CaOCl_(2)`
= milli mole of `Cl_(2)=` milli mole of `CaOCl_(2)`
So, molarity `=6/25 M=0.24 M`.
Correct Answer – c
Correct Answer – A
Bleaching powder is `Ca(OCI)CI`. It contains `OCI^(-)` ion and the corresponding acid is HCIO. The anhydride of HCIO is :
`underset(HOCI)overset(HOCI)(+) to H_(2)O + CI_(2)O`