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Ramesh Prasad Bhat
Asked: 2022-11-07T15:56:04+05:30 In:

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n*octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n*octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.

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  1. (i) Cyclohexane and n-octane both are non-polar. Hence they mix completely in all proportions. 

    (ii) KCl is an ionic compound while n-octane is nonpolar. Hence, KCl will not dissolve at all in n-octane. 

    (iii) CH3OH and CH3CN both are polar but CH3CN is less polar than CH3OH. As the solvent is non-polar, CH3CN will dissolve more than CH3OH is n-octane. 

    Thus the order of solubility will be KCl< CH3OH < CH3CN < Cyclohexane.

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Satish Binoya Nadkarni
Asked: 2022-11-03T23:14:05+05:30 In:

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN. 

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN. 

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  1. n-octane is a non-polar solvent. Therefore, the solubility of a non-polar solute is more than that of a polar solute in the n-octane.

     The order of increasing polarity is:

     Cyclohexane < CH3CN < CH3OH < KCl Therefore, the order of increasing solubility is: KCl < CH3OH < CH3CN < Cyclohexane 

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Bijoy Rao Dayal
Asked: 2022-10-31T18:20:11+05:30 In:

Based on solute `-` solvent interactions, arrange the following in order of increasing solubility in `n-`octane and explain the result. Cyclohexane, `KCl,CH_(3)OH,CH_(3)CN`.

Based on solute `-` solvent interactions, arrange the following in order of increasing solubility in `n-`octane and explain the result. Cyclohexane, `KCl,CH_(3)OH,CH_(3)CN`.
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  1. (a) Cyclohexane and n-octane both are non-polar. They mix completely in all proportions.
    (b) KCl is an ionic compound, KCl will not dissovle in n-octane.
    (c ) `CH_(3)OH` is polar. `CH_(3)OH` will dissolve in n-octane.
    (d) `CH_(3)CN` is polar but lesser than `CH_(3)OH`. Therefore, it will dissolve in n-octane but to a greater extent as compared to `CH_(3)OH`. Hence, the oreder is `KCl lt CH_(3)OH lt CH_(3)CN lt “Cyclohexane”`.

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