Correct Answer – B

Let the base, height and area of the first triangle be b₁ , h₁ , and A₁ respectively. Let the base, height and area of the second triangle be b₂ , h₂ and A₂ respectively.

A₁/A₂ = (b₁ x h₁)/(b₂ x h₂) …[Ratio of areas of two tringles is equal to the product of their bases and corresponding ]

A₁/A₂ = (9 x 5)/(10 x 6)

= 45/60

A₁/A₂ = 3/4

∴ The ratio of areas of the tringles is 3:4.

Let the base height and area of the first triangle be `b_(1),h_(1)` and `A_(1)` respectively. Let the base, height and area of the second triangle be `b_(2),h_(2)` and `A_(2)` respectively.
`b_(1)=9,h_(1)=5,b_(2)=10` and `h_(2)=6`.
The ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights.
`(A_(1))/(A_(2))=(b_(1)xxh_(1))/(b_(2)xxh_(2))`
`:.(A_(1))/(A_(2))=(9xx5)/(10xx6):.(A_(1))/(A_(2))=3/4`
The ratio of the areas of the triangles is 3:4.