ATV tower has a height of 150m. By how much the height of tower be increased to double its coverage range ?
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Here,
`h = 150 m`,
`d = sqrt(2 Rh) rArr d_(1) = 2d`
`sqrt(2RH_(1)) = 2 sqrt(2Rh) rArr 2Rh_(1) = 4 (2Rh)`
`h_(1) = 4h`
`h = 4 xx 150 = 600 m`
`:.` Increase in height of tower `= 600 – 150 = 450m`