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Poonam Ghanshyam Thaman
Asked: 2022-11-09T08:39:25+05:30 In:

At 298 K, the heat of solution of `MgSO_(4) (s)` is `-91.21 kJ mol^(-1)` and that of `MgSO_(4). 7H_(2)O(s)` is 13.81 kJ `mol^(-1)`. Calclate heat of hydration of `MgSO_(4)(s)` i.e., `DeltaH` for the reaction
`MgSO_(4)(s)+7H_(2)O(l) to MgSO_(4).7H_(2)O(s)`
A. `-105.02 kJ mol^(-1)`
B. `105.02 kJ mol^(-1)`
C. `-77.40 kJ mol^(-1)`
D. `77.40 kJ mol^(-1)`

At 298 K, the heat of solution of `MgSO_(4) (s)` is `-91.21 kJ mol^(-1)` and that of `MgSO_(4). 7H_(2)O(s)` is 13.81 kJ `mol^(-1)`. Calclate heat of hydration of `MgSO_(4)(s)` i.e., `DeltaH` for the reaction
`MgSO_(4)(s)+7H_(2)O(l) to MgSO_(4).7H_(2)O(s)`
A. `-105.02 kJ mol^(-1)`
B. `105.02 kJ mol^(-1)`
C. `-77.40 kJ mol^(-1)`
D. `77.40 kJ mol^(-1)`
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1 Answer

  1. Correct Answer – A
    `DeltaH=H_(P) – H_(R), DeltaH=H_(MgSO_(4))-H_(MgSO_(4).7 H_(2)O)`

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