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Neerendra Prasad Kapur
Asked: 2022-11-02T00:24:34+05:30 In:

At` 25^@ `, the density of ` 15 M H_(2)SO_(4) `is ` 1.8 g cm^(-3) ` .Thus mass percentage of ` H_(2)SO_(4) ` in aqueous solution is
A. ` 2% `
B. ` 81.6% `
C. ` 18% `
D. ` 1.8% `

At` 25^@ `, the density of ` 15 M H_(2)SO_(4) `is ` 1.8 g cm^(-3) ` .Thus mass percentage of ` H_(2)SO_(4) ` in aqueous solution is
A. ` 2% `
B. ` 81.6% `
C. ` 18% `
D. ` 1.8% `
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  1. Correct Answer – B
    `18 M H_(2)SO_(4)`means `18 mol L^(-1) 1000 mL of H_(2)SO_(4)` solution has`H_(2)SO_(4) = 18 mol =15xx98 g`
    Also, `1000 mL = 1000 xx 1.8 g H_(2)SO_(4)` solution thus ,`(1000xx1.8)g H_(2)SO_(4)` solution has `H_(2)SO_(4) = 15xx98 g`
    `100 g H_(2)SO_(4)` solution has
    `H_(2)SO_(4) = (15xx98)/(1000xx1.8)=(1470)/(1800)=81.6%`
    Thus , mass percentage of` H_(2)SO_(4) = 81.6%`

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