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Daanish Kumar Anthony
Asked: 2022-11-11T08:44:56+05:30 In:

An electron in the hydrogen atom absorbs energy and jumps to the 4th orbit. Then it jumps back to the ground state in steps, i.e., from 4th to 3rd orbit, then from 3rd to 2nd orbit and finally to the ground state.
The total number of lines produced in the spectrum will be
A. 3
B. 6
C. 9
D. 12

An electron in the hydrogen atom absorbs energy and jumps to the 4th orbit. Then it jumps back to the ground state in steps, i.e., from 4th to 3rd orbit, then from 3rd to 2nd orbit and finally to the ground state.
The total number of lines produced in the spectrum will be
A. 3
B. 6
C. 9
D. 12
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  1. Correct Answer – B
    Total no. of lines produced when the electron returns to the ground state
    `Sigma (n_(2) – n_(1)) = Sigma (4 -1) = Sigma 3 = 3 + 2 + 1 = 6`

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Nayan Ramachandran
Asked: 2022-11-09T21:13:52+05:30 In:

An electron in the hydrogen atom absorbs energy and jumps to the 4th orbit. Then it jumps back to the ground state in steps, i.e., from 4th to 3rd orbit, then from 3rd to 2nd orbit and finally to the ground state.
If `lamda_(1)` is the wavelength of the line for jump of the electron from 4th to 3rd orbit and `lamda_(2)` that of the line for jump from 3rd to 2nd orbit, then wavelength of the line for the jump from 4th orbit to 2nd orbit will be
A. `lamda_(1) + lamda_(2)`
B. `(lamda_(1) lamda_(2))/(lamda_(1) + lamda_(2))`
C. `(lamda_(1) lamda_(2))/(lamda_(1) – lamda_(2))`
D. `(lamda_(1) + lamda_(2))/(lamda_(1) lamda_(2))`

An electron in the hydrogen atom absorbs energy and jumps to the 4th orbit. Then it jumps back to the ground state in steps, i.e., from 4th to 3rd orbit, then from 3rd to 2nd orbit and finally to the ground state.
If `lamda_(1)` is the wavelength of the line for jump of the electron from 4th to 3rd orbit and `lamda_(2)` that of the line for jump from 3rd to 2nd orbit, then wavelength of the line for the jump from 4th orbit to 2nd orbit will be
A. `lamda_(1) + lamda_(2)`
B. `(lamda_(1) lamda_(2))/(lamda_(1) + lamda_(2))`
C. `(lamda_(1) lamda_(2))/(lamda_(1) – lamda_(2))`
D. `(lamda_(1) + lamda_(2))/(lamda_(1) lamda_(2))`
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  1. Correct Answer – D
    `bat(v)_(1) = (1)/(lamda_(1)) = R ((1)/(3^(2)) – (1)/(4^(2)))`
    `bar(v)_(2) = (1)/(lamda_(2)) = R ((1)/(2^(2)) – (1)/(3^(2)))`
    `bar(v) = (1)/(lamda) = R ((1)/(2^(2)) – (1)/(4^(2)))`
    Hence, `(1)/(lamda) = (1)/(lamda_(1)) + (1)/(lamda_(2)) = (lamda_(1) + lamda_(2))/(lamda_(1) lamda_(2)) or lamda = (lamda_(1) lamda_(2))/(lamda_(1) + lamda_(2))`

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