ABCD is a trapezium in which AB ∥ DC. If the length of AB and CD is 17 cm and 13 cm, the height of the trapezium is 12 cm, then find the area of trapezium.
1. 120 cm2
2. 198 cm2
3. 180 cm2
4. 210 cm2
1. 120 cm2
2. 198 cm2
3. 180 cm2
4. 210 cm2
Correct Answer – Option 3 : 180 cm2
Given:
ABCD is a trapezium, AB ∥ DC
AB = 17 cm
CD = 13 cm
Height of the trapezium = 12 cm
Formula Used:
Area of trapezium = 1/2 × height × (Sum of parallel sides)
Calculation:
Area of trapezium = 1/2 × height × (Sum of parallel sides)
⇒ 1/2 × 12 × (17 + 13)
⇒ 6 × 30
⇒ 180
∴ The area of trapezium is 180 cm2.