A transverse wave propagating on a stretched string of linear density 3 × 10-4 kg m-1 is represented by the equation, y = 0.2 sin (1.5x + 60t)
Where x is in metres and t is in seconds. The tension in the string (in newtons) is:
(a) 0.24
(b) 0.48
(c) 1.20
(d) 1.80
(a) 0.48
v = \(\sqrt{\frac{T}{m}}\) = \(\frac{ω}{k}\)
⇒ T = (\(\frac{ω}{k}\))2 m = \((\frac{60}{1.5})^2\) x 3 x 10–4
= 0.48 N