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Aayushi Jaggi
Asked: 2022-11-11T18:47:59+05:30 In:

A system goes from P to Q by two different paths in the `p-V` diagram as shown in figure. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2 ?
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A system goes from P to Q by two different paths in the `p-V` diagram as shown in figure. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2 ?
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  1. For path 1, Heat given `Q_(1)` = + 1000J ltBrgt Work done = `W_(1)` (let)
    For path 2,
    `” “` Work done `(W_(2))=(W_(1)-100)J`
    Heat given `Q_(2)`= ?
    As change in internal energy between two states for different path is same.
    `therefore ” “DeltaU=Q_(1)-W_(1)=Q_(2)-W_(2)`
    `” “1000-W_(1)=Q_(2)-(W_(1)-100)`
    `rArr” “Q_(2)=1000-100=900J`

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Radha Gole
Asked: 2022-11-08T11:28:02+05:30 In:

A system goes from P to Q by two different paths in the `P-V` diagram as shown in (figure). Heat given to the system in path 1 is `1000J`. The work done by the system along path 1 is more than path 2 by `100J`. What is the exchange by the system in path 2?
image

A system goes from P to Q by two different paths in the `P-V` diagram as shown in (figure). Heat given to the system in path 1 is `1000J`. The work done by the system along path 1 is more than path 2 by `100J`. What is the exchange by the system in path 2?
image
Parabola
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1 Answer

  1. In (figure) `dQ_(1)= dU+dW_(1)`
    and `Q_(2)=dU+dW_(2)`
    `:. dQ_(1)-dQ_(2)= dW_(1)-dW_(2)`
    `1000-dQ_(2)= 100`
    `dQ_(2)= 1000-100= 900J`

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