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Jawahar Chatterjee
Asked: 2022-11-05T14:23:07+05:30 In:

A solution prepared by dissolving 1.25 g of oil of winter green (methyl salicylate) in 99.0 g of benzene has a boling point of `80.31^(@)C`. Determine the molar mass of this compound (B.P. Of pure benzene = `80.10^(@)C`, and `K_(b)` for benzene= `2.53^(@)K kg mol^(-1))`

A solution prepared by dissolving 1.25 g of oil of winter green (methyl salicylate) in 99.0 g of benzene has a boling point of `80.31^(@)C`. Determine the molar mass of this compound (B.P. Of pure benzene = `80.10^(@)C`, and `K_(b)` for benzene= `2.53^(@)K kg mol^(-1))`
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  1. `M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xxW_(A))`
    `K_(b)=2.53 K kg mol^(-1),W_(B)=1.25g, W_(A)=99.0g=0.099 kg, DeltaT_(b)=(80.31-80.10)=0.21^(@)=0.21K`
    `M_(B)=((2.53K kgmol^(-1))xx(1.25g))/((0.21K)xx(0.099 kg))=152.12 g mol^(-1)`

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