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Zaad Batta
Asked: 2022-11-12T00:06:17+05:30 In:

A solid whose volume does not change with temperature floats in a liquid. For two different temperatures `t_1` and `t_2` of the liqiud, fraction `f_1` and `f_2` of the volume of the solid remain submerged in the liquid. The coefficient of volume expansion of the liquid is equal to
A. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`
B. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`
C. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`
D. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`

A solid whose volume does not change with temperature floats in a liquid. For two different temperatures `t_1` and `t_2` of the liqiud, fraction `f_1` and `f_2` of the volume of the solid remain submerged in the liquid. The coefficient of volume expansion of the liquid is equal to
A. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`
B. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`
C. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`
D. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`
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1 Answer

  1. Correct Answer – A
    `W+p_(t_1)f_(1)Vg=rho_(t_(2))f_(2)vg`
    `rho_(t_(1))f_(1)=rho_(t_(2))f_(2)`
    `(rho_(0)/(1+gammat_(2)))f_(1) =(rho_(0)/(1+gammat_(0)))f_(2)`
    `(1+gammat_(2))f_(1)=(1+gammat_(1))f_(2)`
    `f_(1)-f_(2)=(f_(2)t_(1)-f_(1)t_(2))`
    `gamma=(f_(1)-f_(2))/(f_(2)t_(1)-f_(1)t_(2))`

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