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Surya Jagat Muni
Asked: 2022-11-08T08:14:55+05:30 In:

A solid is in the form of a right circular cone mounted on ahemisphere. The radius of the hemisphere is 3.5cm and the height of the coneis 4cm. The solid is placed in a cylindrical tub, full of water, in such away that the whole solid is submerged in water. If the radius of the cylinderis 5cm and its height is 10.5cm, find the volume of water left in thecylindrical tub. `(U s epi=(22)/7)`

A solid is in the form of a right circular cone mounted on ahemisphere. The radius of the hemisphere is 3.5cm and the height of the coneis 4cm. The solid is placed in a cylindrical tub, full of water, in such away that the whole solid is submerged in water. If the radius of the cylinderis 5cm and its height is 10.5cm, find the volume of water left in thecylindrical tub. `(U s epi=(22)/7)`
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  1. Given, `r=3.5cm` `h=4cm`
    `R=5cm` `H=10.5cm`
    Volume of water left in the cylinder=Volume of cylinder-(volume of cone + volume of hemisphere)=`piR^2H-((pi/3)r^2h + 2/3pir^3)`=`(825-(51.33+89.83)) cm^3`
    (put (`pi=22/7)`)
    =`683.84cm^3`

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