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Himanshu Lodi
Asked: 2022-11-06T12:23:33+05:30 In:

A sinusoidal voltage of peak value `200` volts is connected to a diode and resistor `R` in the circuit shown so that half wave rectification occurs. If the forward resistance of the diode is negligible compared to `R` the `rms` voltage (in volt) across `R` is approximately
image
A. 200
B. 100
C. `200/(sqrt(2))`
D. 280

A sinusoidal voltage of peak value `200` volts is connected to a diode and resistor `R` in the circuit shown so that half wave rectification occurs. If the forward resistance of the diode is negligible compared to `R` the `rms` voltage (in volt) across `R` is approximately
image
A. 200
B. 100
C. `200/(sqrt(2))`
D. 280
Parabola
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1 Answer

  1. Correct Answer – B
    Output of the circuit will be a half wave
    `V_(rms)` of half wave `=200/2=100 V`

    • 0
Hemendra Hayre
Asked: 2022-10-31T08:53:40+05:30 In:

A sinusoidal voltage of peak value `200` volts is connected to a diode and resistor `R` in the circuit shown so that half wave rectification occurs. If the forward resistance of the diode is negligible compared to `R` the `rms` voltage (in volt) across `R` is approximately
image
A. `200`
B. `100`
C. `200/(sqrt(3))`
D. `280`

A sinusoidal voltage of peak value `200` volts is connected to a diode and resistor `R` in the circuit shown so that half wave rectification occurs. If the forward resistance of the diode is negligible compared to `R` the `rms` voltage (in volt) across `R` is approximately
image
A. `200`
B. `100`
C. `200/(sqrt(3))`
D. `280`
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – B
    `V_(rms)=(V_(0))/2=200/2=100V`

    • 0