A silicon diode is connected to a load resistance `R_(L)` as shown in the figure. If `V_(in)=15V` and `R_(L)=10kOmega`
(a) If barrier voltage, `V_(B)=0.7V` then calculate
(i) output voltage across `R_(L)`
(ii) current in diode and ltbRgt (iii) forward resistance.
(b) If diode is assumed ideal, then what will be
(i) output voltage and
(ii) output current in diode?
(a) If barrier voltage, `V_(B)=0.7V` then calculate
(i) output voltage across `R_(L)`
(ii) current in diode and ltbRgt (iii) forward resistance.
(b) If diode is assumed ideal, then what will be
(i) output voltage and
(ii) output current in diode?

(a) (i) `V_(out)=V_( i n)-V_(B)=15-0.7=14.3V`
(ii) `L=(V_(out))/(R_(L))=(14.3)/(10xx10^(3))=1.43mA`
(iii) `r_(f)=(V_(B))/(I)=(0.7)/(1.43xx10^(-3))=490Omega`
(b) For ideal diode, `r_(f)=0,V_(B)=0`
(i) `V_(out)=V_(i n)=15V`
(ii) ` I=(V_(out))/(RF_(L))=(15)/(10xx10^(3))=1.5mA`