A plant virus is found to consist of uniform cylindrical particle of `150 Å` in diameter 5000 Å long. The specific volume of the virus is 0.75 `mLg^(-1)`. If the virus is considered to be a single particle, find its molar mass.
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Percentage loss in mass`=2xx(18)/(266.5)xx100=13.50%`
Specific volume`=(“Volume”)/(“Mass”)`
Mass`=(pir^(2)H)/(“Specific Volume”)`
`=(3.14xx(75xx10^(-8))^(2)xx5000xx10^(-8))/(0.75)`
Molar mass `=` Mass `xxN`
`(3.14xx(75xx10^(-8))^(2)xx5000xx10^(-8))/(0.a5)xx6.023xx10^(23)`
`=7.092xx10^(7)g`