A particle executes simple harmonic motion along the x-axis. The force acting on it is given by?
(a) Acos(kx)
(b) Ae^(-kx)
(c) Akx
(d) –Akx
(a) Acos(kx)
(b) Ae^(-kx)
(c) Akx
(d) –Akx
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Correct answer is (d) –Akx
The best explanation: F=-Akx implies that the force is proportional or displacement and acts in its opposite direction. So it represents simple harmonic motion.