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Gulab Baber More
Asked: 2022-11-08T20:45:14+05:30 In:

A multiple choice emamination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just guessing is
A. `(17)/(3^(5))`
B. `(13)/(3^(5))`
C. `(11)/(3^(5))`
D. `(10)/(3^(5))`

A multiple choice emamination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just guessing is
A. `(17)/(3^(5))`
B. `(13)/(3^(5))`
C. `(11)/(3^(5))`
D. `(10)/(3^(5))`
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  1. Correct Answer – C
    Answer for any question can be guessed in 3 ways. `therefore` Probability that any question is correct `=1/3`
    From five questions if at least four questions are correctly answered then required probability
    = Probability that four questins are correctly answered
    + Probability that five questions are correctly answered
    `=””^(5)C_(4)((1)/(3))^(4)((2)/(3))+””^(5)C_(5)((1)/(3))^(5)=(11)/(3^(5))`

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