A mass (M), attached to a horizontal spring, executes S.H.M. whith amplitude `A_(1). When the mass (M) passes throgh its mean position then shaller mass (m) is placed over it and both of them move together with amplitude `A_(2). The ration of.
A. (a) `(M+m)/M`
B. (b) (M/(M+m)^(1/2)`
C. (c ) ((M+m)/M)^1/2)`
D. (d) M/(M+m)`
A. (a) `(M+m)/M`
B. (b) (M/(M+m)^(1/2)`
C. (c ) ((M+m)/M)^1/2)`
D. (d) M/(M+m)`
Correct Answer – C
(c ) The net force becomes zero at the mean point.
Therefore, linear momentum must be conserved.
:. Mv_(1)=(M+m)v_(2)`
`Masqrtk/M=(M+m)A_(2)sqrtk/(m+M):. (V=Asqrtk/M)`
`A_(1)sqrtM=A_(2)sqrtM+m :. A_(1)/A_(2)=sqrt(m+M)/M`.