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Rajesh Nanda
Asked: 2022-11-07T11:45:04+05:30 In:

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to `mg` in magnitude
B. constant and greater than `mg` in magnitude
C. variable but always greater than `mg`.
D. at first greater than `mg`, and later becomes equal to `mg`.

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to `mg` in magnitude
B. constant and greater than `mg` in magnitude
C. variable but always greater than `mg`.
D. at first greater than `mg`, and later becomes equal to `mg`.
Parabola
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  1. Correct Answer – D
    When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case.
    `R =` reactional force = friction + mg
    `rArr R gt mg`
    When the man gets straight up in that case friction `= 0`
    `rArr “Reactional force” = mg`.

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Aarif Varun Bawa
Asked: 2022-11-07T11:42:12+05:30 In:

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude
B. constant and greater than mg in magnitude
C. variable but always greater than mg
D. at first greater than mg and later becomes equal to mg

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude
B. constant and greater than mg in magnitude
C. variable but always greater than mg
D. at first greater than mg and later becomes equal to mg
Parabola
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1 Answer

  1. (d) When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case.
    R=reactional force=friction+mg
    `Rightarrow Rgtmg`
    When the man gets straight up in that case friction=0
    Reactional force=mg

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Aastha Mangat
Asked: 2022-11-04T07:06:20+05:30 In:

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude
B. constant and greater than mg in magnitude
C. variable but always greater than mg
D. at first greater than mg and later becomes eual to mg

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude
B. constant and greater than mg in magnitude
C. variable but always greater than mg
D. at first greater than mg and later becomes eual to mg
Parabola
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1 Answer

  1. Correct Answer – D
    (d) When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case.
    R=reactional froce`=”friction” +mg rArr R gt mg`
    When the man gets straight up in that case friction ~~ 0
    `rArr” ” “Rectional force” ~~mg`

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Binita Banerjee
Asked: 2022-11-01T00:12:57+05:30 In:

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude.
B. constant and greater than mg in magnitude
C. variable but always greater than mg.
D. at first greater than mg, and later becomes equal to mg.

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to mg in magnitude.
B. constant and greater than mg in magnitude
C. variable but always greater than mg.
D. at first greater than mg, and later becomes equal to mg.
Parabola
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  1. Correct Answer – D
    In the process of getting straight up and stand from squatting position, the man exerts a variable force (F) on the ground to set his body in motion. This force is in addition to the force required to support his weight (mg). Once the man is in standing position, F becomes zero.

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Gauransh Sachar
Asked: 2022-10-31T14:11:22+05:30 In:

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to `mg` in magnitude.
B. constant and greater than `mg` in magnitude.
C. variable but always greater than `mg`.
D. at first greater than `mg`, and later becomes equal to `mg`

A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.
A. constant and equal to `mg` in magnitude.
B. constant and greater than `mg` in magnitude.
C. variable but always greater than `mg`.
D. at first greater than `mg`, and later becomes equal to `mg`
Parabola
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1 Answer

  1. Correct Answer – D
    When the man gets straight up and sstand, reaction of ground on the man `=`mg. However, when he is squatting on the ground, reactio of ground is more than `mg`, as the man is to exert sone extra force on the ground to stand up .

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