A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder.
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`/_ABC` is a right angled triangle
so, by Pythagoras theorem
`AC^2=AB^2+BC^2`
`AC^2=6^2+2.5^2`
`AC^2=42.25m^2`
`AC=sqrt42.25 m`